(2t-3)^2=2t+5t-26

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Solution for (2t-3)^2=2t+5t-26 equation: 



(2t-3)^2=2t+5t-26

We move all terms to the left:

(2t-3)^2-(2t+5t-26)=0

We add all the numbers together, and all the variables

(2t-3)^2-(7t-26)=0

We get rid of parentheses

(2t-3)^2-7t+26=0

We add all the numbers together, and all the variables

-7t+(2t-3)^2+26=0

We move all terms containing t to the left, all other terms to the right

-7t+(2t-3)^2=-26

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